How do you evaluate ${cos}^{- 1} (cos (\frac{5 π}{6}))$ $cos^-1(cos((5pi)/6))$ ?

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How do you evaluate ${cos}^{- 1} (cos (\frac{5 π}{6}))$ $cos^-1(cos((5pi)/6))$ ?

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Answer 1 · 2016-07-09T15:41:59

$\frac{5 π}{6}$ $(5pi)/6$

Explanation:

The ${cos}^{- 1} x$ $cos^-1x$ is the inverse function of cosx

and $color(red)(|bar(ul(color(white)(a/a)color(black)(cos^-1(cosx)=x)color(white)(a/a)|))$

$rArrcos^-1(cos((5pi)/6))=(5pi)/6$

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How do you evaluate ${cos}^{- 1} (cos (\frac{5 π}{6}))$ $cos^-1(cos((5pi)/6))$ ?

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How do you evaluate cos^-1(cos((5pi)/6))cos−1(cos(5π6))cos^-1(cos((5pi)/6))?

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How do you evaluate ${cos}^{- 1} (cos (\frac{5 π}{6}))$ $cos^-1(cos((5pi)/6))$ ?