How do you evaluate ${cos}^{- 1} (cos (\frac{7 π}{6}))$ $cos^-1(cos((7pi)/6))$ ?

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How do you evaluate ${cos}^{- 1} (cos (\frac{7 π}{6}))$ $cos^-1(cos((7pi)/6))$ ?

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Answer 1 · 2016-03-18T15:07:37

$= 5 \frac{π}{6}$ $=5pi/6$ least value

Explanation:

${cos}^{- 1} (cos (7 \frac{π}{6})) = {cos}^{- 1} (cos (π + \frac{π}{6})) = {cos}^{- 1} (- cos (\frac{π}{6})) = {cos}^{- 1} (cos (π - \frac{π}{6})) = {cos}^{- 1} (cos (5 \frac{π}{6})) = 5 \frac{π}{6}$ $cos^-1(cos(7pi/6))=cos^-1(cos(pi+pi/6))=cos^-1(-cos(pi/6))=cos^-1(cos(pi-pi/6))=cos^-1(cos(5pi/6))=5pi/6$

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How do you evaluate ${cos}^{- 1} (cos (\frac{7 π}{6}))$ $cos^-1(cos((7pi)/6))$ ?

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How do you evaluate ${cos}^{- 1} (cos (\frac{7 π}{6}))$ $cos^-1(cos((7pi)/6))$ ?