How do you evaluate ${cos}^{- 1} (cos (- \frac{π}{3}))$ $cos^-1 (cos(-pi/3))$ ?

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How do you evaluate ${cos}^{- 1} (cos (- \frac{π}{3}))$ $cos^-1 (cos(-pi/3))$ ?

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Answer 1 · 2017-01-01T20:16:18

Like every other inverse, the inverse cosine "undoes" the cosine, therefore, ${cos}^{- 1} (cos (- \frac{π}{3})) = - \frac{π}{3}$ $cos^-1(cos(-pi/3)) = -pi/3$

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How do you evaluate ${cos}^{- 1} (cos (- \frac{π}{3}))$ $cos^-1 (cos(-pi/3))$ ?

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How do you evaluate ${cos}^{- 1} (cos (- \frac{π}{3}))$ $cos^-1 (cos(-pi/3))$ ?