How do you evaluate $cos (\frac{- 4 π}{3})$ $cos((-4pi)/3)$ ?

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How do you evaluate $cos (\frac{- 4 π}{3})$ $cos((-4pi)/3)$ ?

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Answer 1 · 2016-08-15T16:30:09

$- \frac{1}{2}$ $- 1/2$

Explanation:

Trig table of special arcs, and unit circle -->
$cos (\frac{- 4 π}{3}) = cos (\frac{4 π}{3}) = cos (\frac{π}{3} + π) = - cos (\frac{π}{3}) = - \frac{1}{2}$ $cos ((-4pi)/3) = cos ((4pi)/3) = cos (pi/3 + pi) = - cos (pi/3) = -1/2$

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How do you evaluate $cos (\frac{- 4 π}{3})$ $cos((-4pi)/3)$ ?

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How do you evaluate $cos (\frac{- 4 π}{3})$ $cos((-4pi)/3)$ ?