How do you evaluate $cos (arctan \sqrt{3} + a r c cot \sqrt{3})$ $cos(arctan sqrt 3 + arc cot sqrt3)$ ?

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How do you evaluate $cos (arctan \sqrt{3} + a r c cot \sqrt{3})$ $cos(arctan sqrt 3 + arc cot sqrt3)$ ?

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Answer 1 · 2016-04-25T02:20:43

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Explanation:

If $a = a r c tan x, and b + a r c cot x$ $a = arc tan x, and b + arc cot x$ , the principal values of a and b are complementary and differ by $\frac{π}{2}$ $pi/2$ . The general values differ by an odd multiple of $\frac{π}{2}$ $pi/2$ .

Anyway, cos ( arc tan x + arc cot x ) = cos ( odd multiple of $\frac{π}{2}$ $pi/2$ ) = 0.
Here, x = $\sqrt{3}$ $sqrt 3$ ..

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How do you evaluate $cos (arctan \sqrt{3} + a r c cot \sqrt{3})$ $cos(arctan sqrt 3 + arc cot sqrt3)$ ?

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Explanation:

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How do you evaluate $cos (arctan \sqrt{3} + a r c cot \sqrt{3})$ $cos(arctan sqrt 3 + arc cot sqrt3)$ ?