How do you evaluate $cos ({cos}^{- 1} (\frac{1}{2}))$ $cos(cos^-1(1/2))$ without a calculator?

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How do you evaluate $cos ({cos}^{- 1} (\frac{1}{2}))$ $cos(cos^-1(1/2))$ without a calculator?

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Answer 1 · 2017-02-19T20:56:20

$\frac{1}{2}$ $1/2$

Explanation:

$cos and {cos}^{- 1} are the inverse of each other$ $cos " and " cos^-1" are the inverse of each other"$

$and f (f^{- 1} (x)) = x \leftarrow in general$ $"and "f(f^-1(x))=xlarr"in general"$

$\Rightarrow cos ({cos}^{- 1} (\frac{1}{2})) = \frac{1}{2}$ $rArrcos(cos^-1(1/2))=1/2$

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How do you evaluate $cos ({cos}^{- 1} (\frac{1}{2}))$ $cos(cos^-1(1/2))$ without a calculator?

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How do you evaluate $cos ({cos}^{- 1} (\frac{1}{2}))$ $cos(cos^-1(1/2))$ without a calculator?