How do you evaluate #cos(cos^-1(1/2))# without a calculator?
1 Answer
Feb 19, 2017
Explanation:
#cos " and " cos^-1" are the inverse of each other"#
#"and "f(f^-1(x))=xlarr"in general"#
#rArrcos(cos^-1(1/2))=1/2#