How do you evaluate $cos ({cos}^{- 1} (- \frac{\sqrt{3}}{2}))$ $cos(cos^-1(-sqrt3/2))$ ?

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Answer 1 · 2016-07-25T09:55:58

$- \frac{\sqrt{3}}{2}$ $-sqrt 3/2$

Use $f f^{- 1} a = a$ $f f^(-1)a=a$

Here, $f = cos, f^{- 1} = {cos}^{- 1} and a = - \frac{\sqrt{3}}{2}$ $f = cos, f^(-1)=cos^(-1) and a = -sqrt 3/2$ .

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