How do you evaluate ${cot}^{- 1} (\frac{1}{\sqrt{3}})$ $cot^-1(1/sqrt3)$ without a calculator?

Question

8923 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-16T14:46:07

$arc cot (\frac{1}{\sqrt{3}}) = \frac{1}{3} π$ $"arc"cot(1/sqrt3)=1/3pi$

Let $θ = arc cot (\frac{1}{\sqrt{3}})$ $theta="arc"cot(1/sqrt3)$

$cot θ = \frac{1}{\sqrt{3}}$ $cottheta=1/sqrt3$

$tan θ = \sqrt{3}$ $tantheta=sqrt3$

This is one of the angles you should know and works out to be $\frac{1}{3} π$ $1/3pi$

How do you evaluate cot−1(1√3)cot^-1(1/sqrt3) without a calculator?