How do you evaluate $cot (arcsin(5/6))$ ?

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Answer 1 · 2015-09-04T05:52:11

$sqrt11 /5$

Let arc $sin (5/6)= theta$

$sin theta=5/6$ , that means $csc theta =6/5$

$cot^2 theta= csc^2 theta -1= 11/25$

$cot theta= sqrt11 /5$ , that means $theta= arc cot (sqrt11 /5)$

Hence $cot arc sin (5/6)= cot arc cot (sqrt11/5)= sqrt11/5$

How do you evaluate cot (arcsin(5/6))cot (arcsin(5/6))?