How do you evaluate #csc^-1 (-7/3)#?

1 Answer
Jun 5, 2016

#theta = -25.3769" to 4 decimal places"# (clockwise -> 4rd quadrant)

Explanation:

#"cosec"(theta)" is "1/sin(theta)#

#=>"cosec"(theta)" is "1/[("opposite")/("hypotenuse")] =("hypotenuse")/("opposite")-> -7/3#

Tony B

I have made #y# negative so that we have #=-7/3#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
From the diagram #sin(theta)=-3/7#

So #sin^(1)(-3/7) = theta = -25.3769# to 4 decimal places