How do you evaluate #csc[arc cos(-4/5)]#?
1 Answer
Aug 3, 2016
Explanation:
Let
Then, #cos a = -4/5, sin a = sqrt(1-cos^2a)=3/5.
The given expression = csc a = 1/sin a=5/3#. .
Let
Then, #cos a = -4/5, sin a = sqrt(1-cos^2a)=3/5.
The given expression = csc a = 1/sin a=5/3#. .