Question

How do you evaluate `f(x)=x^2-3x+1` for `f(5)`?

Answer 1

11

Explanation:

To evaluate f(5) substitute x = 5 into f(x).

`f(color(red)(5))=(color(red)(5))^2-(3xxcolor(red)(5))+1`

`rArrf(5)=25-15+1=11`