How do you evaluate $f(x)=x^2-3x+1$ for $f(5)$ ?

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Answer 1 · 2016-09-25T13:10:52

11

To evaluate f(5) substitute x = 5 into f(x).

$f(color(red)(5))=(color(red)(5))^2-(3xxcolor(red)(5))+1$

$rArrf(5)=25-15+1=11$

How do you evaluate f(x)=x^2-3x+1f(x)=x^2-3x+1 for f(5)f(5)?