How do you evaluate $\frac{5 \times 10^{- 3}}{8 \times 10^{- 2}}$ $\frac { 5\times 10^ { - 3} } { 8\times 10^ { - 2} }$ ?

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Answer 1 · 2017-06-14T06:40:30

$\frac{5 \times 10^{- 3}}{8 \times 10^{- 2}} = 6.25 \times 10^{- 2}$ $(5xx10^(-3))/(8xx10^(-2))=6.25xx10^(-2)$

$\frac{5 \times 10^{- 3}}{8 \times 10^{- 2}}$ $(5xx10^(-3))/(8xx10^(-2))$

= $\frac{5}{8} \times \frac{10^{- 3}}{10^{- 2}}$ $5/8xx10^(-3)/10^(-2)$

= $0.625 \times 10^{(- 3 - (- 2))}$ $0.625xx10^((-3-(-2)))$

= $0.625 \times 10^{(- 3 + 2)}$ $0.625xx10^((-3+2))$

= $0.625 \times 10^{- 1}$ $0.625xx10^(-1)$

= $\frac{6.25}{10} \times 10^{- 1}$ $6.25/10xx10^(-1)$

= $6.25 \times 10^{- 1 - 1}$ $6.25xx10^(-1-1)$

= $6.25 \times 10^{- 2}$ $6.25xx10^(-2)$

How do you evaluate 5×10−38×10−2\frac { 5\times 10^ { - 3} } { 8\times 10^ { - 2} }?