How do you evaluate $h(2)$ given $h(t)=t^3+5t^2$ ?

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Answer 1 · 2016-08-14T09:42:06

$h(2)=28$

$h(t)=t^3+5t^2$

$h(2)=2^3+5(2^2)$

$=8+5times4$

$=8+20$

$=28$

Answer 2 · 2016-08-14T09:47:10

h(2) = 28

To evaluate h(2), substitute t = 2 into h(t).

$h(color(red)(2))=(color(red)(2))^3+5(color(red)(2))^2$

$rArrh(2)=(2xx2xx2)+(5xx2xx2)=8+20=28$

How do you evaluate h(2)h(2) given h(t)=t^3+5t^2h(t)=t^3+5t^2?