How do you evaluate $h (- 2)$ $h(-2)$ given $h (x) = 3 x^{2} + 2 - 2 x$ $h(x)=3x^2+2-2x$ ?

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Answer 1 · 2018-03-19T22:29:27

See a solution process below:

For each occurrence of $x$ $color(red)(x)$ in $h (x)$ $h(x)$ substitute $- 2$ $color(red)(-2)$ and evaluate the expression:

$h (x) = 3 x^{2} + 2 - 2 x$ $h(color(red)(x)) = 3color(red)(x)^2 + 2 - 2color(red)(x)$ becomes:

$h (- 2) = (3 \cdot {(- 2)}^{2}) + 2 - (2 \cdot - 2)$ $h(color(red)(-2)) = (3 * (color(red)(-2))^2) + 2 - (2 * color(red)(-2))$

$h (- 2) = (3 \cdot 4) + 2 - (- 4)$ $h(color(red)(-2)) = (3 * 4) + 2 - (-4)$

$h (- 2) = 12 + 2 + 4$ $h(color(red)(-2)) = 12 + 2 + 4$

$h (- 2) = 14 + 4$ $h(color(red)(-2)) = 14 + 4$

$h (- 2) = 18$ $h(color(red)(-2)) = 18$

How do you evaluate h(−2)h(-2) given h(x)=3x2+2−2xh(x)=3x^2+2-2x?