How do you evaluate $h (7)$ $h(7)$ given $h (t) = t + 1$ $h(t)=t+1$ ?

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Answer 1 · 2018-05-23T12:54:12

$h (7) = 8$ $h(7)=8$

$substitute t = 7 into h (t)$ $"substitute t = 7 into "h(t)$

$h (7) = 7 + 1 = 8$ $h(color(red)(7))=color(red)(7)+1=8$

How do you evaluate h(7)h(7) given h(t)=t+1h(t)=t+1?