Question

How do you evaluate `int (x^2-1)/( x+1) dx` for [1, 2]?

Answer 1

`1/2`

Explanation:

`int_1^2(x^2-1)/(x+1)dx=int_1^2((x+1)(x-1))/(x+1)dx`
=`int_1^2(x-1)dx=x^2/2-x|_1^2`
=`2^2/2-2-(1/2-1)`
=`1/2`