How do you evaluate $k(-6)$ given $k(n)=n+2$ ?

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Answer 1 · 2016-08-13T21:00:00

$k(-6)=-4$

$k(n)=n+2$

or

$k(-6)=-6+2$

or
$k(-6)=-4$

Answer 2 · 2016-08-13T21:00:54

$k(-6) = -4$

All the fancy notation just means that $n = -6$
Replace $n$ by the value $-6$

$k(color(red)n) = color(red)n+2$

$:.k(color(red)(-6)) = color(red)(-6)+2 = -4$

How do you evaluate k(-6)k(-6) given k(n)=n+2k(n)=n+2?