Question

How do you evaluate `log 0.5915`?

Answer 1

`log_10 0.5915 = -0.22805`

Explanation:

Possibly not the kind of answer you were hoping for, but the only reasonable way to do this is to use a calculator (that has a log function).

You are looking for a value, `x` such that
`color(white)("XXXX")10^x = 0.5915`

Since `10^0=1 and 10^(-1)=0.1`
and since `1 > 0.5915 > 0.1`
`rarr color(white)("XXXX") 0 > x > -1`

We could try different values between `0 and -1` as the exponent, but without a calculator (or similar technology) such evaluations are too time consuming to be reasonable.