How do you evaluate $log_(1/2) (1/32)$ ?

Question

5884 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-12T12:47:31

1/5

Use $log_b a=log_c a/log_c b$

Here,

$log_(1/2) (1/32)$

$=log(1/32)/log(1/2)$

$=(-log 2)/(-log 32)$

$=log 2/log 2^5$

$=log 2/(5 log 2)$

$=1/5$

How do you evaluate log_(1/2) (1/32)log_(1/2) (1/32)?