Question

How do you evaluate `log_(1/3) (1/81)`?

Answer 1

`4`

Explanation:

recall that `log_2(8)=3, => 2^3=8`

Let `log_(1/3)(1/81)=a`

`(1/3)^a=1/81`

`(1/(3^a)) =1/81`

`3^a=81`

`a=4`