How do you evaluate ${log}_{\frac{1}{6}} (\frac{1}{36})$ $log_(1/6) (1/36)$ ?

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How do you evaluate ${log}_{\frac{1}{6}} (\frac{1}{36})$ $log_(1/6) (1/36)$ ?

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Answer 1 · 2016-11-04T15:18:06

$n = 2$ $n=2$

Explanation:

Using the $law of logarithms$ $color(blue)"law of logarithms"$

$color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=nhArrx=b^n)color(white)(2/2)|)))$

$rArr1/36=(1/6)^n=1/6^n$

$rArr1/6^2=1/6^nrArrn=2" is the value"$

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How do you evaluate ${log}_{\frac{1}{6}} (\frac{1}{36})$ $log_(1/6) (1/36)$ ?

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