How do you evaluate ${log}_{\frac{1}{9}} (\frac{1}{81})$ $log_(1/9) (1/81)$ ?

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Answer 1 · 2016-11-11T07:43:43

${log}_{\frac{1}{9}} (\frac{1}{81}) = 2$ $log_(1/9)(1/81)=2$

As ${(\frac{1}{9})}^{2} = \frac{1}{81}$ $(1/9)^2=1/81$ ,

by the definition of logarithm that $if a^b=m$ , then $log_a m=b$ , we get

$log_(1/9)(1/81)=2$

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