Question

How do you evaluate `log_343 3`?

Answer 1

`log_343 3=0.1882`

Explanation:

Let `log_343 3=x`

then `343^x=3`

or `log(343^x)=log3`

or `x xx log343=log3`

or `x=log3/log343=0.4771/2.5353=0.1882`

Hence, `log_343 3=0.1882`