How do you evaluate $log_4 4^-0.38$ ?

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Answer 1 · 2016-11-30T22:04:48

I got $-0.38$

We can take the exponent in front of the log and write:

$-0.38log_4(4)=$

but $log_4(4)=1$ (from the definition of log) so you get:

$-0.38*1=-0.38$

How do you evaluate log_4 4^-0.38log_4 4^-0.38?