Question

How do you evaluate `log_6(root5 36)`?

Answer 1

`2/5`

Explanation:

Use `log_a a= 1 and log(a^m)^n=log a^(mn)=mn log a`.

`log_6root(5) 36=log_6root(5) (6^2)=log_6((root(5)6)^2)=log_6 6^(2/5)=(2/5)log_6 6=2/5`