Question

How do you evaluate `log_7 (7^(2x))`?

Answer 1

`log_7(7^(2x))=2x`

Explanation:

As `log_a p^n=nlog_a p` and `log_a a=1`

`log_7(7^(2x))`

= `2xlog_7 7`

= `2x xx1=2x`