How do you evaluate $log_8 (1/4)$ ?

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Answer 1 · 2015-12-20T13:25:15

I found $-2/3$

We can try to use the change of base formula to change into a log in base $2$ and get:
$log_8(1/4)=(log_2(1/4))/(log_2(8))=(-2)/3$

How do you evaluate log_8 (1/4)log_8 (1/4)?