Question

How do you evaluate `Log _ 9(1/3)`?

Answer 1

`color(white)(xx)-1/2`

Explanation:

`color(white)(xx)log_9 (1/3)=log_(3^2) 3^-1`
`color(white)(xxxxxxxx)=1/2xx(-1)log_3 3`
`color(white)(xxxxxxxx)=-1/2`