How do you evaluate $log136^8+log136^17$ ?

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Answer 1 · 2015-12-27T09:13:35

$log 136^8+log 136^17 = 25 log 136 ~~ 53.3384727$

If $a > 0$ then $log a^b = b log a$

So:

$log 136^8 + log 136^17 = 8 log 136 + 17 log 136 = 25 log 136$

$~~ 25*2.133538908 = 53.3384727$

How do you evaluate log136^8+log136^17 log136^8+log136^17?