How do you evaluate $s^{2} t \div 10$ $s^2tdiv10$ for s=-2 and t=-10?

Question

1332 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-28T01:47:45

$- 4$ $-4$

First, rewrite this problem as:

$\frac{s^{2} t}{10}$ $(s^2t)/10$

Now you can substitute the given values for $s$ $s$ and $t$ $t$ to evaluate the expression:

$\frac{(- 2^{2}) \cdot (- 10)}{10}$ $((-2^2)*(-10))/10$

$\frac{(- 2 \cdot - 2) \cdot (- 10)}{10}$ $((-2* -2)*(-10))/10$

$\frac{4 \cdot (- 10)}{10}$ $(4*(-10))/10$

$- \frac{40}{10}$ $-40/10$

$- 4$ $-4$

How do you evaluate s2t÷10s^2tdiv10 for s=-2 and t=-10?