How do you evaluate #sec^-1(-2)# without a calculator?

1 Answer
Sep 30, 2016

#x = \pm (2\pi)/3#.

Explanation:

What do you mean exactly with that exponent #-1#?

If you mean the power, we have

#sec(x)=1/cos(x) \implies sec^{-1}(x) = 1/(1/cos(x))=cos(x)#

Thus, #sec^{-1}(-2)=cos(-2)#, and I see no way to calculate it manually.

If you mean the inverse function, we want to find a number #x# such that #sec(x)=-2#, or if you prefer, #1/cos(x)=-2#

This clearly leads to #cos(x)=-1/2#, and it is a known angle: #x = \pm (2\pi)/3#, depending on which interval you choose to invert the cosine function.