How do you evaluate #sec^-1(sec((11pi)/6))#?
1 Answer
Jul 26, 2016
Explanation:
#sec^-1" and" sec "are " color(blue)"inverse functions"# and in general
#color(red)(|bar(ul(color(white)(a/a)color(black)(f^-1(f(x))=x)color(white)(a/a)|)))#
#rArrsec^-1(sec((11pi)/6))=(11pi)/6#
