Question

How do you evaluate `sec^-1(sec((11pi)/6))`?

Answer 1

`(11pi)/6`

Explanation:

`sec^-1" and" sec "are " color(blue)"inverse functions"`

and in general `color(red)(|bar(ul(color(white)(a/a)color(black)(f^-1(f(x))=x)color(white)(a/a)|)))`

`rArrsec^-1(sec((11pi)/6))=(11pi)/6`