Question

How do you evaluate `sec^-1(sec(-(pi)/6))`?

Answer 1

`-pi/6`

Explanation:

successive operations by a function f and its inverse #f^(-1), either

way, on an operand, returns the operand.

Here, f is `sec`, `f^(-1)` is `sec^(-1)` and the operand is `-pi/6`..

So, `sec^(-1) sec (-pi/6)=-pi/6`.