How do you evaluate #sec(cos^-1(1/2))# without a calculator?

2 Answers
Oct 23, 2016

#sec(cos^(-1)(1/2)) = 2#

Explanation:

Another way, without calculating #cos^(-1)(1/2)#:

Consider a right triangle with an angle #theta = cos^(-1)(1/2)#. Then #cos(theta) = 1/2#, meaning the ratio of its adjacent side to the hypotenuse is #1/2#. Thus the ratio of the hypotenuse to its adjacent side, that is, #sec(theta)#, is #2/1 = 2#.

Thus #sec(cos^(-1)(1/2)) = sec(theta) = 2#

Note that this same reasoning shows that in general, #sec(cos^(-1)(x)) = 1/x#

Mar 12, 2017

#2#

Explanation:

Understand that #color(blue)(cos^-1(1/2)=cos(theta)=(1/2)#

As we know that, cosine function is the reciprocal of secant function,

#color(brown)(sec(theta)=1/(cos(theta))#

#rarrsec(theta)=1/(1/2)#

#rArrsec(theta)=2#

Hope this helps... :)