How do you evaluate $sec ({sec}^{- 1} (- \frac{2}{\sqrt{3}}))$ $sec(sec^-1(-2/sqrt3))$ ?

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Answer 1 · 2016-08-10T16:27:57

$- \frac{2}{\sqrt{3}}$ $-2/sqrt 3$

uSE $F F^{- 1} (a) = a$ $F F^(-1)(a) = a$

Here, $F i s sec, F,^{_1} i s {sec}^{- 1} and a = (- \frac{2}{\sqrt{3}})$ $F is sec, F,^(_1) is sec^(-1) and a = (-2/sqrt 3)$ .

How do you evaluate sec(sec−1(−2√3))sec(sec^-1(-2/sqrt3))?