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How do you evaluate $sec ({sec}^{- 1} (- 27))$ $sec(sec^-1(-27))$ ?

1 Answer

Jan 16, 2017

(- 27)

Explanation:

${sec}^{- 1} (- 27) - \to a r c sec (- 27)$ $sec^-1 (- 27) --> arcsec (-27)$
$sec (a r c sec (- 27)) = - 27$ $sec (arcsec (-27)) = - 27$

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