How do you evaluate $sec ({sec}^{- 1} (\frac{5}{2}))$ $sec(sec^-1(5/2))$ ?

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How do you evaluate $sec ({sec}^{- 1} (\frac{5}{2}))$ $sec(sec^-1(5/2))$ ?

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Answer 1 · 2016-12-17T05:26:11

$\frac{5}{2}$ $5/2$

Explanation:

${sec}^{- 1} (\frac{5}{2}) - \to a r c sec (\frac{5}{2})$ $sec^-1 (5/2) --> arcsec (5/2)$
sec of $a r c sec (\frac{5}{2})$ $arcsec (5/2)$ --> $\frac{5}{2}$ $5/2$

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How do you evaluate $sec ({sec}^{- 1} (\frac{5}{2}))$ $sec(sec^-1(5/2))$ ?

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