How do you evaluate $sec ({tan}^{- 1} (8))$ $sec(tan^-1(8))$ without a calculator?

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How do you evaluate $sec ({tan}^{- 1} (8))$ $sec(tan^-1(8))$ without a calculator?

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Answer 1 · 2016-08-28T12:16:17

$\sqrt{65}$ $sqrt65$

Explanation:

${tan}^{- 1} (8)$ $tan^-1(8)$ means the angle whose tan is 8
Draw a right angle triangle with two shorter sides 8 and 1
Mark in $θ$ $theta$ opposite the side length 8.
The hypotenuse is length $\sqrt{65}$ $sqrt65$ -Pythagoras
The sec of $θ$ $theta$ is hypotenuse divided by adjacent

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How do you evaluate $sec ({tan}^{- 1} (8))$ $sec(tan^-1(8))$ without a calculator?

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Science

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How do you evaluate sec(tan−1(8))sec(tan^-1(8)) without a calculator?

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Explanation:

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How do you evaluate $sec ({tan}^{- 1} (8))$ $sec(tan^-1(8))$ without a calculator?