Question

How do you evaluate `sin^-1(cos(pi/3))`?

Answer 1

`pi/6` or 30deg

Explanation:

Let say `x=sin^-1(cos(pi/3))`
`sin(x) = cos(pi/3)`
`sin(x) = 1/2`
`x=sin^-1(1/2)`
`x=pi/6` or 30deg