How do you evaluate ${sin}^{- 1} (cos (\frac{π}{3}))$ $sin^-1(cos(pi/3))$ ?

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How do you evaluate ${sin}^{- 1} (cos (\frac{π}{3}))$ $sin^-1(cos(pi/3))$ ?

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Answer 1 · 2017-01-12T09:49:25

$\frac{π}{6}$ $pi/6$ or 30deg

Explanation:

Let say $x = {sin}^{- 1} (cos (\frac{π}{3}))$ $x=sin^-1(cos(pi/3))$
$sin (x) = cos (\frac{π}{3})$ $sin(x) = cos(pi/3)$
$sin (x) = \frac{1}{2}$ $sin(x) = 1/2$
$x = {sin}^{- 1} (\frac{1}{2})$ $x=sin^-1(1/2)$
$x = \frac{π}{6}$ $x=pi/6$ or 30deg

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How do you evaluate ${sin}^{- 1} (cos (\frac{π}{3}))$ $sin^-1(cos(pi/3))$ ?

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