How do you evaluate $sin^-1(sin((-2pi)/3))$ ?

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Answer 1 · 2016-06-04T07:40:01

$-(2pi)/3$ .

If y = f(x) and the inverse relation is $x = f^(-1)(y)$ , then

$f(f^(-1)(y) )=y and f^(-1)(f(x))=x$ . The operands are returned as the values.

Here, the operand is $-(2pi)/3$ , and so, the value is $-(2pi)/3$ .

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How do you evaluate sin^-1(sin((-2pi)/3))sin^-1(sin((-2pi)/3))?