How do you evaluate ${sin}^{- 1} (sin (\frac{π}{10}))$ $sin^-1(sin((pi)/10))$ ?

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Answer 1 · 2016-07-08T16:38:58

$\frac{π}{10}$ $pi/10$ .

Use ${sin}^{- 1} (sin a)$ $sin^(-1)(sin a)$ = the operand a.

Here $a = \frac{π}{10}$ $a = pi/10$

Had it been ${sin}^{- 1} (sin (\frac{9 π}{10}))$ $sin^(-1)(sin( (9pi)/10))$ , instead, the value will be the new

operand $\frac{9 π}{10}$ $(9pi)/10$ .

How do you evaluate sin−1(sin(π10))sin^-1(sin((pi)/10))?