How do you evaluate ${sin}^{- 1} (- \frac{\sqrt{2}}{2})$ $sin^-1(-sqrt(2)/2)$ ?

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Answer 1 · 2016-02-07T00:12:30

It is $- \frac{π}{4}$ $-pi/4$

It is

${sin}^{- 1} (- \frac{\sqrt{2}}{2}) = {sin}^{- 1} (sin (- \frac{π}{4})) = - \frac{π}{4}$ $sin^-1(-sqrt2/2)=sin^-1(sin(-pi/4))=-pi/4$

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