Question

How do you evaluate `Sin^-1 ( sqrt2 / 2)`?

Answer 1

Explanation is given below.

Explanation:

A good idea is to know the trigonometric ratios of the standard angles.

A glance would help you note that `sin(45^o)=sqrt(2)/2`

`sin^-1(sqrt(2)/2) =45^o`

You need to take care that the range of `sin^-1(x)` is `[-90^o,90^o]` That is why we can safely say
`sin^-1(sqrt(2)/2)` is `45^o`