How do you evaluate ${sin}^{- 1} (- \frac{\sqrt{3}}{2})$ $sin^-1 (-sqrt3/2)$ ?

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Answer 1 · 2015-04-19T14:06:50

Your answer is $- \frac{π}{3}$ $-pi/3$ .

Please analyse the file I've created from top to bottom to understand why it's the case...

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How do you evaluate sin−1(−√32)sin^-1 (-sqrt3/2)?