Question

How do you evaluate `sin^-1(sqrt3/2)`?

Answer 1

`pi/3 and (2pi)/3`

Explanation:

`sin^-1 (sqrt3/2)` --> `arcsin (sqrt3/2)`
Use trig table of special arcs and trig unit circle -->
`sin x = sqrt3/2` --> there are 2 solutions:
arc `x = pi/3` and arc `x = (2pi)/3`