Question

How do you evaluate `sin[arccos(-4/5)+arcsin(-3/5)]`?

Answer 1

Find value of `sin[ arccos (-4/5) + arcsin (-3/5)]`

Explanation:

On the trig unit circle.

`cos x = -4/5 = -0.80 --> x = - 143.13`

`sin y = -3/5 = -0.60 --> y = -36.87`

`sin (x + y) = sin (-143.13 - 36.87) = sin (-180) = 0`