How do you evaluate $sin (arctan (\frac{3}{4}))$ $sin(arctan(3/4))$ ?

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Answer 1 · 2016-05-27T12:14:42

$\pm \frac{3}{5}$ $+-3/5$

Let $a = a r c tan (\frac{3}{4})$ $a = arc tan (3/4)$

Then, $tan a = \frac{3}{4} > 0$ $tan a = 3/4>0$ . a iis in the 1st quadrant or in the 3rd.

So, the given expression $sin a = \pm \frac{3}{5}$ $sin a = +-3/5$ .

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