How do you evaluate $sin ({sin}^{- 1} (\frac{3}{5}))$ $sin(sin^-1(3/5))$ ?

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Answer 1 · 2016-07-31T06:16:18

$sin ({sin}^{- 1} (\frac{3}{5})) = \frac{3}{5}$ $sin(sin^-1 (3/5))=3/5$

The solution:

sin^-1 (3/5) is an angle whose sine function is 3/5

Therefore $sin ({sin}^{- 1} (\frac{3}{5})) = \frac{3}{5}$ $sin(sin^-1 (3/5))=3/5$

God bless....I hope the explanation is useful.

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