How do you evaluate #sin(sin^-1(-4/7))#?
1 Answer
Jul 7, 2016
Explanation:
#sin^-1x " is the " color(blue)"inverse" " of "sinx# In this context
#color(red)(|bar(ul(color(white)(a/a)color(black)(sin(sin^-1x)=x)color(white)(a/a)|)))#
#rArrsin(sin^-1(-4/7))=-4/7#
